Logo

PERMUTATIONA

Updated 2024-03-13 13:09:18.090000

Syntax

SELECT [westclintech].[wct].[PERMUTATIONA] (
   <@n, int,>
  ,<@k, int,>)

Description

Use the scalar function PERMUTATIONA to calculate the number of permutations with replacement defined as:

P_{k,n}=n^k

Arguments

@n

Number of items.

@k

Number chosen.

Return Type

float

Remarks

If n < 0 and k < 0 then NULL is returned.

If k < 0 then NULL is returned.

Examples

Example #1

SELECT wct.PERMUTATIONA(10, 3) as PERMUTATIONA;

This produces the following result.

{"columns":[{"field":"PERMUTATIONA","headerClass":"ag-right-aligned-header","cellClass":"ag-right-aligned-cell"}],"rows":[{"PERMUTATIONA":"1000"}]}

Example #2

Calculate the probability of 2 people having the same birthday in a room containing n people.

SELECT x.n,

       1 - wct.PERMUT(365, x.n) / wct.PERMUTATIONA(365, x.n) as [p(n)]

FROM

(

    VALUES

        (10),

        (20),

        (22),

        (23),

        (30),

        (57)

) x (n);

This produces the following result.

{"columns":[{"field":"n","headerClass":"ag-right-aligned-header","cellClass":"ag-right-aligned-cell"},{"field":"p(n)","headerClass":"ag-right-aligned-header","cellClass":"ag-right-aligned-cell"}],"rows":[{"n":"10","p(n)":"0.116948177711078"},{"n":"20","p(n)":"0.41143838358058"},{"n":"22","p(n)":"0.47569530766255"},{"n":"23","p(n)":"0.507297234323985"},{"n":"30","p(n)":"0.706316242719269"},{"n":"57","p(n)":"0.99012245934117"}]}

See Also

FACTORIALPOWER - the step-h factorial power x(n,h)

LCHOOSE - Natural logarithm of the binomial coefficient

LPERMUT - Calculate the natural logarithm of the PERMUT function.

LPERMUTA - calculate the natural logarithm of the PERMUTATIONA function.

PERMUT - calculate the number of permutations for a given number objects that can be selected from a number of objects