PERMUTATIONA
Updated 2024-03-13 13:09:18.090000
Syntax
SELECT [westclintech].[wct].[PERMUTATIONA] (
<@n, int,>
,<@k, int,>)
Description
Use the scalar function PERMUTATIONA to calculate the number of permutations with replacement defined as:
P_{k,n}=n^k
Arguments
@n
Number of items.
@k
Number chosen.
Return Type
float
Remarks
If n < 0 and k < 0 then NULL is returned.
If k < 0 then NULL is returned.
Examples
Example #1
SELECT wct.PERMUTATIONA(10, 3) as PERMUTATIONA;
This produces the following result.
{"columns":[{"field":"PERMUTATIONA","headerClass":"ag-right-aligned-header","cellClass":"ag-right-aligned-cell"}],"rows":[{"PERMUTATIONA":"1000"}]}
Example #2
Calculate the probability of 2 people having the same birthday in a room containing n people.
SELECT x.n,
1 - wct.PERMUT(365, x.n) / wct.PERMUTATIONA(365, x.n) as [p(n)]
FROM
(
VALUES
(10),
(20),
(22),
(23),
(30),
(57)
) x (n);
This produces the following result.
{"columns":[{"field":"n","headerClass":"ag-right-aligned-header","cellClass":"ag-right-aligned-cell"},{"field":"p(n)","headerClass":"ag-right-aligned-header","cellClass":"ag-right-aligned-cell"}],"rows":[{"n":"10","p(n)":"0.116948177711078"},{"n":"20","p(n)":"0.41143838358058"},{"n":"22","p(n)":"0.47569530766255"},{"n":"23","p(n)":"0.507297234323985"},{"n":"30","p(n)":"0.706316242719269"},{"n":"57","p(n)":"0.99012245934117"}]}
See Also
FACTORIALPOWER - the step-h factorial power x(n,h)
LCHOOSE - Natural logarithm of the binomial coefficient
LPERMUT - Calculate the natural logarithm of the PERMUT function.
LPERMUTA - calculate the natural logarithm of the PERMUTATIONA function.